The hydride complex [Ru(IPr) 2(CO)H][BAr F 4], 1, reacts with InMe 3 with loss of CH 4 to form [Ru(IPr) 2(CO)(InMe)(Me)][BAr F 4], 4, featuring an unsupported Ru−In bond with unsaturated Ru and In centres. 4 reacts with H 2 to give [Ru(IPr) 2(CO)(η 2-H 2)(InMe)(H)][BAr F 4], 5, while CO induces formation of the indyl complex [Ru(IPr) 2(CO) 3(InMe 2)][BAr F 4], 7. These observations highlight the ability of Me to shuttle between Ru and In centres and are supported by DFT calculations on the mechanism of formation of 4 and its reactions with H 2 and CO. An analysis of Ru-In bonding in these species is also presented. Reaction of 1 with GaMe 3 also involves CH 4 loss but, in contrast to its In congener, sees IPr transfer from Ru to Ga to give a gallyl complex featuring an η 6 interaction of one aryl substituent with Ru.
- density functional calculations
- heterometallic complexes
ASJC Scopus subject areas
- Organic Chemistry